HI. How many ATOMS of sulfur are present in 4.25 moles of sulfur tetrafluoride ?
atoms of sulfur.
Sulfur tetra flouride formula is SF4 so there are 4.25 moles of sulfur ATOMS in there.
4.25 moles x 6.022 x 10^23 atoms/mole = 25.59 x 10^23 atoms or 4.25 moles they are the same .....
HI. How many ATOMS of sulfur are present in 4.25 moles of sulfur tetrafluoride ? {nl} atoms of sulfur.
1.02374 • 1025
I have done this in detail, but my answer has disappeared. asinus
Correction
HI. How many ATOMS of sulfur are present in 4.25 moles of sulfur tetrafluoride ?
atoms of sulfur.
\(The \ Avogadro \ constant \ has \ the \ value\)
\({\displaystyle 6{,}022\;140\;857\;\cdot 10^{23}\ \mathrm {mol} ^{-1}}\)
\(1 mol \ SF_4 = 1 mol \ S+ 4mol \ F\)
\(4.25 mol \ SF_4 = 4.25 mol \ S+ 17mol \ F\)
\(4.25mol \ S \times {\displaystyle 6{,}022\;140\;857\;\cdot 10^{23}\ \mathrm {mol} ^{-1}}\)
\(= 2.559 \ 409 \ 864 \ 22 \times 10^{24}S\)
\(2.559 \ 409 \ 864 \ 22 \times 10^{24}S \ are \ present \ in \ 4.25 \ moles \ of \ sulfur \ tetrafluoride.\)
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