Hi I have to calculate the time for the liquid that pass through capillary of distance 25cm and diameter of capillary 50micrometer at a flow rate of 0.1 microlitre /min
+118724 $$$1 cm^3$ is holds of 1ml of fluid\\
So I am going to change all dimensions to cm\\
the length of the capillary is $25cm$\\
The diameter is $50\mu m$ so the radius is $25 \mu m$\\
So the radius is $25\times 10^{-6} m = 25\times 10^{-4} cm$\\
Volume of the tube is $\pi r^2h$\\
$=\pi \times (25*10^{-4})^2\times 25 cm^3$\\
$=\pi\times 625*10^{-8}\times 25 ml$\\
$=\pi \times 15625\times 10^{-8} ml$\\
$ \approx 4.9087385 \times 10^{-4} ml$\\
$\approx 4.9087385 \times 10^{-1}\mu l$\\\\\\
$\frac{0.1\mu l}{1min}$ is equivalent to $\frac{1\mu l}{10min}$which is also equivalent to $\frac{10min}{\mu l}$\\\\
$\frac{10min}{\mu l}\times 4.9087385\times 10^{-1} \mu l=4.9087385$ minutes\\\\
So the process will take almost 5 minutes.$$
That is assuming I have not made any stupid errors!
+118724 $$$1 cm^3$ is holds of 1ml of fluid\\
So I am going to change all dimensions to cm\\
the length of the capillary is $25cm$\\
The diameter is $50\mu m$ so the radius is $25 \mu m$\\
So the radius is $25\times 10^{-6} m = 25\times 10^{-4} cm$\\
Volume of the tube is $\pi r^2h$\\
$=\pi \times (25*10^{-4})^2\times 25 cm^3$\\
$=\pi\times 625*10^{-8}\times 25 ml$\\
$=\pi \times 15625\times 10^{-8} ml$\\
$ \approx 4.9087385 \times 10^{-4} ml$\\
$\approx 4.9087385 \times 10^{-1}\mu l$\\\\\\
$\frac{0.1\mu l}{1min}$ is equivalent to $\frac{1\mu l}{10min}$which is also equivalent to $\frac{10min}{\mu l}$\\\\
$\frac{10min}{\mu l}\times 4.9087385\times 10^{-1} \mu l=4.9087385$ minutes\\\\
So the process will take almost 5 minutes.$$
That is assuming I have not made any stupid errors!
