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# Hi I need

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106
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\displaystyle  \int_1^2 \frac{(x+3)^2}{3} dx\\

Apr 19, 2022

#1
+9459
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Using the substitution $$u = x + 3$$$$du = dx$$, we have the change of integration boundary $$\begin{cases}x = 1 \implies u= 4\\x = 2 \implies u = 5\end{cases}$$. Then we have $$\displaystyle\int_1^2 \dfrac{(x + 3)^2}3\,dx =\dfrac13\int_4^5u^2\,du$$. You can use the power rule to integrate it. Note that $$\displaystyle\int_a^b f(x)\,dx = F(b) - F(a)$$ where F is an antiderivative of f.

Apr 19, 2022
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i need teaching of this pls help

Kakashi  Apr 19, 2022
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+9459
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You can pretty much learn on your own using some online resources.

MaxWong  Apr 19, 2022
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They are called integrals, and anti- derivatives. you can search them up :)

Guest Apr 19, 2022
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Kakashi, you are being a pest.