1(x-2)+2/(x-1)=6/x
somehow I cannpt solve it, please find x
thank you for all your good work
+33616 Is this meant to be 1/(x-2) + 2/(x-1) = 6/x ?
If so, multiply all terms by x(x-1)(x-2) to get x(x-1) + 2x(x-2) = 6(x-1)(x-2)
Simplify: x^2 - x + 2x^2 - 4x = 6x^2 -18x +12
Collect like terms 3x^2 -5x = 6x^2 -18x +12
Subtract 3x^2 from and add 5x to both sides: 0 = 3x^2 - 13x +12
This factors as (3x - 4)(x - 3) = 0
So x = 4/3 and x = 3
