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$$\\Cos\;\frac{(3\sqrt3+4)}{5\sqrt{10}}\\\\$$
If this angle is in radian then it =0.8355
if it is in degrees then it is.
$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\frac{\left({\mathtt{3}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{3}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}\right)}{\left({\mathtt{5}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{10}}}}\right)}}\right)} = {\mathtt{0.999\: \!948\: \!477\: \!928}}$$
Are you sure that your question is correct??
$$\\Cos\;\frac{(3\sqrt3+4)}{5\sqrt{10}}\\\\$$
If this angle is in radian then it =0.8355
if it is in degrees then it is.
$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\frac{\left({\mathtt{3}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{3}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}\right)}{\left({\mathtt{5}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{10}}}}\right)}}\right)} = {\mathtt{0.999\: \!948\: \!477\: \!928}}$$