what do you do when you get this when completing the square of a quadratic equation?

\(x = \frac{2-2\sqrt{3}}{2}\)

do you remove the zero? or not? please help!

Guest Jul 5, 2017

#1**+2 **

I think...your radical needs a ± sign in front of it..

\(x=\frac{2\pm2\sqrt3}{2} \\~\\ x=\frac{2(1\pm\sqrt3)}{2} \\~\\ x=1\pm\sqrt3\) We can reduce this fraction by 2 .

So, your exact solutions are:

x = 1 + √3 and x = 1 - √3

We can get approximate solutions by putting it into a calculator:

x ≈ 2.732 and x ≈ -0.732

These should be the x values that cause the y to equal zero.

Does that help any? I don't know what you mean by " remove the zero " .

hectictar Jul 5, 2017

#1**+2 **

Best Answer

I think...your radical needs a ± sign in front of it..

\(x=\frac{2\pm2\sqrt3}{2} \\~\\ x=\frac{2(1\pm\sqrt3)}{2} \\~\\ x=1\pm\sqrt3\) We can reduce this fraction by 2 .

So, your exact solutions are:

x = 1 + √3 and x = 1 - √3

We can get approximate solutions by putting it into a calculator:

x ≈ 2.732 and x ≈ -0.732

These should be the x values that cause the y to equal zero.

Does that help any? I don't know what you mean by " remove the zero " .

hectictar Jul 5, 2017