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what do you do when you get this when completing the square of a quadratic equation?

 

\(x = \frac{2-2\sqrt{3}}{2}\)

do you remove the zero? or not? please help!

Guest Jul 5, 2017

Best Answer 

 #1
avatar+7324 
+2

I think...your radical needs a  ±  sign in front of it..

 

\(x=\frac{2\pm2\sqrt3}{2} \\~\\ x=\frac{2(1\pm\sqrt3)}{2} \\~\\ x=1\pm\sqrt3\)               We can reduce this fraction by 2  .

 

 

So, your exact solutions are:

x  =  1 + √3        and         x  =  1 - √3

 

We can get approximate solutions by putting it into a calculator:

x  ≈  2.732         and         x  ≈  -0.732

 

These should be the  x  values that cause the  y  to equal zero.

Does that help any? I don't know what you mean by  " remove the zero " .

hectictar  Jul 5, 2017
 #1
avatar+7324 
+2
Best Answer

I think...your radical needs a  ±  sign in front of it..

 

\(x=\frac{2\pm2\sqrt3}{2} \\~\\ x=\frac{2(1\pm\sqrt3)}{2} \\~\\ x=1\pm\sqrt3\)               We can reduce this fraction by 2  .

 

 

So, your exact solutions are:

x  =  1 + √3        and         x  =  1 - √3

 

We can get approximate solutions by putting it into a calculator:

x  ≈  2.732         and         x  ≈  -0.732

 

These should be the  x  values that cause the  y  to equal zero.

Does that help any? I don't know what you mean by  " remove the zero " .

hectictar  Jul 5, 2017

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