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Find the equation of the line tangent to the given curve at the indicated point.

y = x^2 + 8x at (2, 20)

--> I got y-20 = 10(x-2)

y = x^3 – 4x at (3, 15)

--> I had trouble with this one....

 Aug 11, 2018
edited by Guest  Aug 11, 2018
edited by Guest  Aug 11, 2018
 #1
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"Find the equation of the line tangent to the given curve at the indicated point.

y = x^2 + 8x at (2, 20)

--> I got y-20 = 10(x-2)

y = x^3 – 4x at (3, 15)"

 

.

 Aug 11, 2018
edited by Alan  Aug 11, 2018

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