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+5

555

2

Hi there,

I have tried this problem to this point...how to do further?

${5+{1\over x^3}}\over{-4\over y^2}+3$

$= {{5x^3+1}\over{x^3}}/{{-4+3y^2}\over{y^2}}$

$= {{5x^3+1}\over x^3} * {{y^2}\over -4+3y^2}$

$= {5x^3y^2+y^2}\over -4x^3+3x^2y^2$

$=2+y^2\over -4x^3+1$

Is this the answer?..Thanx to anyone who is willing to assist..

Guest Feb 1, 2016

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Melody · Answer 1 · 2016-02-01T11:11:06

Hi,

The second last line looks right but the last line is not correct. :/ (why did you think it was?)

I don't think you can go further than the second last line. I might leave the factorising in but it doesn't matter.

Guest · Answer 2 · 2016-02-01T12:51:40

Hi Melody,

it's me, Juriemagic...

uhm, well, this problem is actually one I found on the link you posted me a few days ago on negative indices. I actually notice now that I made an error. I should have had the last line as $= {2x+y^2}\over-4x^3+1$

because I'm thinking that the ${5x^3y^2}\over 3x^2y^2$ leaves ${2x}$ ?

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