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The circle centered at \((2, -1) \) and with radius \(4\) intersects the circle centered at \((2, 5)\) and with radius \(\sqrt10\) at two points \(A\) and \(B\). Find \((AB)^2\).

 Jun 2, 2020
 #1
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From the distance formula, AB^2 = 28.

 Jun 2, 2020

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