The function f satisfies\( f(\sqrt{x + 1}) = \frac{1}{x}\)for all \(x \ge -1, x\neq 0\). Find f(2).
\(f(2)=f(\sqrt{x+1})\)
solve for x
\(2=\sqrt{x+1}\)
\(2^2=\sqrt{x+1}^2\)
\(4=x+1\)
\(3=x\)
now plug \(x=3\) into \(f(\sqrt{x+1})\)
\(f(2)=f(\sqrt{x+1})=1/x\)
\(f(2)=f(\sqrt{3+1})=1/3\)
Therefore, f(2) = 1/3
