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What is the polar form of the equation?

(x+2)^2+y^2=4

r^2=4r cosθ

r(r+4cosθ)=0

r^2=4r sinθ

r(r+4sinθ)=0

 May 3, 2022
 #1
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Note that the graph of (x + 2)^2 + y^2 = 4 is a circle centered at (-2, 0) and with radius 2.

 

Generally, for a circle centered at (a, b) and with radius R, the polar form is (r cos θ - a)^2 + (r sin θ - b)^2 = R^2.

 

Can you plug in the numbers and simplify from here?

 May 3, 2022
 #2
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sure i could try, thank you

Guest May 3, 2022

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