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# Hmm

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Four positive integers a, b, c, and d satisfy

ab + a + b = 524

bc+c+c=146

cd+c+d=104

abcd=8!

a) What is a-d

b) what are a,b,c,d

These problems go off each other, so you can use part a for part b. Please explain how you solved the problem.

Mar 27, 2019

#1
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bc+c+c=156 NOT 146.

If that is correct, then through simple substitutions, you should get the following values:

a = 20, b = 24, c = 6, d = 14

With above values, ALL your 4 equations balance out.

Mar 28, 2019
#2
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No guest-it is 146.

#3
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I think this is a past asked question. Maybe it would be helpful to check it out here!

https://web2.0calc.com/questions/help-fast_9

-Daisy

dierdurst  Mar 29, 2019
#4
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I suspected that there was a mistake in your 2nd equation, when I suggested that 146 might be 156. But, you didn't check it carefully enough, since now it is quite obvious where the mistake is in that equation.

You have it as: bc + c + c =146 instead of: bc + B + c = 146.

Mar 29, 2019
#5
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ah thank you guest