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146
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Four positive integers a, b, c, and d satisfy

ab + a + b = 524

bc+c+c=146

cd+c+d=104

abcd=8!

 

a) What is a-d

b) what are a,b,c,d

 

These problems go off each other, so you can use part a for part b. Please explain how you solved the problem.
 

 Mar 27, 2019
 #1
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I believe your 2nd equation should read:

bc+c+c=156 NOT 146.

If that is correct, then through simple substitutions, you should get the following values:

a = 20, b = 24, c = 6, d = 14

With above values, ALL your 4 equations balance out.

 Mar 28, 2019
 #2
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No guest-it is 146.

Badada  Mar 28, 2019
 #3
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I think this is a past asked question. Maybe it would be helpful to check it out here!

 

https://web2.0calc.com/questions/help-fast_9

 

-Daisy

dierdurst  Mar 29, 2019
 #4
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Thanks dierdurst for that link.

To "Badada": Look at the link provided above and see where you made the MISTAKE!!.

I suspected that there was a mistake in your 2nd equation, when I suggested that 146 might be 156. But, you didn't check it carefully enough, since now it is quite obvious where the mistake is in that equation.

You have it as: bc + c + c =146 instead of: bc + B + c = 146.

 Mar 29, 2019
 #5
avatar+322 
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ah thank you guest

Badada  Mar 29, 2019

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