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a box has a width (x), where (x) is prime. If the box has a height of (x+2), and a length of (x-1), and volume is 140, what is (x)

 Dec 19, 2020
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a box has a width (x), where (x) is prime. If the box has a height of (x+2), and a length of (x-1), and volume is 140, what is (x)

 

Hello Guest!

 

\(V=w\cdot h\cdot l\)

\(400=x\cdot (x+2)\cdot (x-1)\\ (x^2+2x)\cdot (x-1)={\color{red}(400\ not\ correct)}\ 140\ (excuse\ me,\ please!)\\ x^3-x^2+2x^2-2x={\color{red}(400)}\ 140\\ x^3+x^2-2x-{{\color{red}(400)}\ 140}=0 \)    

                                                            

With x = 5, the volume of the box is 140.

smiley  !

 Dec 19, 2020
edited by asinus  Dec 19, 2020
edited by asinus  Dec 19, 2020

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