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# homework help please

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a box has a width (x), where (x) is prime. If the box has a height of (x+2), and a length of (x-1), and volume is 140, what is (x)

Dec 19, 2020

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a box has a width (x), where (x) is prime. If the box has a height of (x+2), and a length of (x-1), and volume is 140, what is (x)

Hello Guest!

$$V=w\cdot h\cdot l$$

$$400=x\cdot (x+2)\cdot (x-1)\\ (x^2+2x)\cdot (x-1)={\color{red}(400\ not\ correct)}\ 140\ (excuse\ me,\ please!)\\ x^3-x^2+2x^2-2x={\color{red}(400)}\ 140\\ x^3+x^2-2x-{{\color{red}(400)}\ 140}=0$$

With x = 5, the volume of the box is 140.

!

Dec 19, 2020
edited by asinus  Dec 19, 2020
edited by asinus  Dec 19, 2020