Thank you in advance for helping me solve this. Can I please get it today before 6:30 pm if possible please!
YA + AZ + BZ + BX + + CX + CY =78
(CY + YA) + (AZ + BZ) + ( BX + CX) = 78
But AC = (1/3)(CY + YA + AC) ⇒ AC - (1/3)AC = (1/3) (CY + YA) ⇒
(2/3)AC = (1/3)(CY + YA) ⇒ 2AC = (CY + CA)
Similarly
2AB = (AZ + BZ)
And
2BC = (BX + CX)
So
2 ( AC + AB + BC) = (CY + CA) + ( AZ + BZ) + (BX + CX)
2 ( AC + AB + BC) = 78
(AC + AB + BC) = 39 = perimeter of ABC
CORRECTED ANSWER......