+0  
 
0
71
4
avatar+464 

Thank you in advance for helping me solve this. Can I please get it today before 6:30 pm if possible please!

 

shreyas1  Oct 8, 2018
 #1
avatar+92463 
+2

 YA + AZ + BZ + BX + + CX + CY  =78

 

(CY + YA)  + (AZ + BZ)  +  ( BX  + CX)  = 78

 

But AC  = (1/3)(CY + YA + AC)    ⇒  AC - (1/3)AC  = (1/3) (CY + YA) ⇒

(2/3)AC  = (1/3)(CY + YA)  ⇒  2AC  = (CY + CA)

 

Similarly

2AB = (AZ + BZ)

 

And

2BC  = (BX + CX)

 

 

So

 

2 ( AC + AB + BC)  = (CY + CA) + ( AZ + BZ) + (BX + CX)

2 ( AC + AB + BC)  =  78

(AC + AB + BC)  = 39  =  perimeter of ABC

 

CORRECTED ANSWER......

 

 

cool cool cool

CPhill  Oct 8, 2018
edited by CPhill  Oct 8, 2018
 #2
avatar+464 
+1

When I tried to check the answer of 26, it said that it was wrong. Can you please walk me through your thought process please.

shreyas1  Oct 8, 2018
 #3
avatar+92463 
+1

See my corrected answer, shreyas1

 

 

cool cool cool

CPhill  Oct 8, 2018
 #4
avatar+464 
0

Thank you CPhill, I was working with you while you were composing an answer and I was going over my thought process and you proved it to me that I was right, once again Thank You

shreyas1  Oct 9, 2018

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