I'm not great at probability.....but I'll see what I can do for you......
First off, the number of total outcomes possible from drawing 4 b***s out of 12 is just C(12,4) = 495......this will be the denominator in our answers......
P(4white or 4blue) = P(4white) + P(4blue) - P(4 white and 4 blue)
The last thing = 0 (We can't draw 4 white ones and 4 blue ones at the same time)
P(4white) = choose any 4 of the 7 white ones = C(7,4) = 35
P(4blue) = choose any 4 from the 5 blue ones = C(5,4) = 5
So we have (35 + 5)/495 = 40/495 = 8/99
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P(3white).....choose 3 of the 7 white ones and 1 of the 5 blue ones =
C(7,3) * C(5,1) = 175.....so we have
175/495 = 35/99
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P(at least 3 white) = P(3white) + P(4white) =
(175 + 35)/ 495 = 210/495 = 42/99 = 14/33
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If another answerer sees any mistakes....feel free to correct me !!
I'm not great at probability.....but I'll see what I can do for you......
First off, the number of total outcomes possible from drawing 4 b***s out of 12 is just C(12,4) = 495......this will be the denominator in our answers......
P(4white or 4blue) = P(4white) + P(4blue) - P(4 white and 4 blue)
The last thing = 0 (We can't draw 4 white ones and 4 blue ones at the same time)
P(4white) = choose any 4 of the 7 white ones = C(7,4) = 35
P(4blue) = choose any 4 from the 5 blue ones = C(5,4) = 5
So we have (35 + 5)/495 = 40/495 = 8/99
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P(3white).....choose 3 of the 7 white ones and 1 of the 5 blue ones =
C(7,3) * C(5,1) = 175.....so we have
175/495 = 35/99
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P(at least 3 white) = P(3white) + P(4white) =
(175 + 35)/ 495 = 210/495 = 42/99 = 14/33
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If another answerer sees any mistakes....feel free to correct me !!