a bag contains 3 blue marbles and 2 green marbles. What is the probability of drawing a blue marble followed by a green marble,without replacing the first marble?
+37170 There are 5 marbles total of which 3 are blue so the chance of getting a blue on on the first draw is 3 out of 5 ... or 3/5 after you draw one marbel out there are 4 left of which 2 are green. The chance of getting green is thus 2 out of 4 or 2/4
Now the chance of getting blue then green is 3/5 x 2/4 = 6/20 = 3/10 or 3 out of 10.
