what line is perpendicular to (-3,-1) when there is a slope of -3/2 going through it?
+23248 A line passes through the point (-3, -1) with a slope of -3/2.
What is the equation of the line perpendicular to that line that passes through that point?
Lines that are perpendicular have slopes that are negative reciprocals.
So, if the first line has a slope of -3/2 the line perpendicular to it will have a slope of 2/3.
Using the point slope form of a line for the line that passes through the point (-3, -1) with a slope of 2/3:
y - y1 = m(x - x1) ---> y - -1 = (2/3)(x - -3) ---> y + 1 = (2/3)(x + 3)
You can simplify that equation: y + 1 = (2/3)x + (2/3)(3)
y + 1 = (2/3)x + 2
y = (2/3)x + 1
