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2a+c=-10
b-c=15
a-2b+c=-5
 Oct 1, 2012
 #1
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Solving Systems Of Equations in Three Variables
 Oct 1, 2012
 #2
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[input]solve( 2a+c=-10, b-c=15, a-2b+c=-5)[/input]
 Oct 2, 2012
 #3
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AldrieeKnight:

2a+c=-10
b-c=15
a-2b+c=-5



How you do it, and not just the answer...

2a+c = -10 --> 2a = -10 - c --> a = -5 - c/2

b-c = 15 --> b = 15 + c

Use these in the final equation.

a - 2b + c = -5 --> - 5 - c/2 - 30 - 2c + c = -5 --> -35 - 3c/2 = -5 --> 3c/2 + 35 = 5 --> 3c/2 = -30 --> c = -20.

Now use this c in the top ones.

a = -5 +20/2 = -5 + 10 = 5

b = 15 + c = 15 - 20 = -5
 Oct 3, 2012

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