A teacher assigned homework to his class and told the students that on each day after the first, they must do twice the number of problems that they had done so far. If at the end of five days, the students had completed one third of the problems, how long will it take them to do all of their problems? Thank you.
+37091 Each day the problems work double so it is a power of two formula
2^5 = 1/3 x where x is the number of problems
solve for x = 96
at 5 days they will have completed 32 of the problems.... the NEXT day they will complete 64 problems for a total of 32 +64 = 96 problems. SO they need ONE more day for a total of 6 days.
+37091 Each day the problems work double so it is a power of two formula
2^5 = 1/3 x where x is the number of problems
solve for x = 96
at 5 days they will have completed 32 of the problems.... the NEXT day they will complete 64 problems for a total of 32 +64 = 96 problems. SO they need ONE more day for a total of 6 days.
Since each day the students will do twice the number of problems already done, when 1/3 of the problems are done at the end of 5 days, the students will do 2/3 of the problems the next day. Hence, they will complete the assignment in one more day. Therefore, it will take them 6 days.
