1.
a) If f(x) = x^2 - 5 find the value of f(-2)
b) Given that f(p) = 11 find both possible values of p.
2.
The area of a shape is given by A (x) = 12x - 2x^2. Find the maximum area of the shape.
Hint - what shape is graph of A(x)?
+37093 1 Just put -2 in place of 'x' f(-2) = (-2)^2-5 == -1
b) SUbstitute 'p' in for 'x' 11= p^2 - 5 Add 5 to both sides
16= p^2 sqrt both sides to find p = +-4
2) this is a parabola that opens downward. The maximum point (I do not know what the maximum AREA is) is given by - b/(2a)
-2x^2 + 12x a = -2 b = 12 - 12/(2(-2)) = 3 is the value of 'x'
SUb this in to find 'y' -2(3^2) + 12 (3) = -18 + 36 = 18 so the max point(x,y) is 3,18
