A ball is thrown horizontally from the top of a building 36.7 m high. The ball strikes the ground at a point 91.9 m from the base of the building. The acceleration of gravity is 9.8 m/s 2. Find the x component of its velocity just before it strikes the ground.

Guest Oct 29, 2019

#1**+1 **

We can find the time that it takes the ball to hit the ground as follows :

-36.7 = (1/2) * -(9.8) * t^2

-36.7 = -4.9 * t^2

(36.7 /4.9) = t^2 take the positive root

t ≈ 2.74 sec

The x component of the velocity remains constant an can be found as

x = v_{x} * t

Where x is the horizontal displacement, v_{x} is the horizontal component of the velocity and t is the time it takes the ball to hit the ground....so....

91.9 = v_{x} * 2.74

91,9 / 2.74 = v_{x} ≈ 33.6 m / s

CPhill Oct 29, 2019