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A ball is thrown horizontally from the top of a building 36.7 m high. The ball strikes the ground at a point 91.9 m from the base of the building. The acceleration of gravity is 9.8 m/s 2. Find the x component of its velocity just before it strikes the ground.

 Oct 29, 2019
 #1
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We can find the time that it takes the ball to hit the ground  as follows :

 

-36.7  = (1/2) * -(9.8) * t^2

 

-36.7  = -4.9 * t^2

 

(36.7 /4.9)   = t^2    take the positive root

 

t ≈  2.74 sec

 

The x component of the velocity remains constant an can be found as

 

x  = vx * t       

 

Where x is the horizontal displacement, vx  is the horizontal component of the velocity and t is the time it takes the ball to hit the ground....so....

 

91.9  = vx  * 2.74

 

91,9 / 2.74  = vx  ≈  33.6 m / s

 

 

cool cool cool

 Oct 29, 2019

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