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If a circular track is 5 meters wide and it takes a horse, running his fastest, π more seconds to run the outer edge than the inner edge, what is his rate per second? Thank you.

 Nov 27, 2016
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Inside distance = 2 π r meters. Where r is inner radius of the track.

 

Outside distance = 2 π(r+5) meters

 

Hence extra distance = 10 π meters

 

Time taken for extra distance =  π seconds

 

Horse's speed = distance/time = 10 π/ π → 10 meters/second

.

 Nov 27, 2016

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