If a circular track is 5 meters wide and it takes a horse, running his fastest, π more seconds to run the outer edge than the inner edge, what is his rate per second? Thank you.
Inside distance = 2 π r meters. Where r is inner radius of the track.
Outside distance = 2 π(r+5) meters
Hence extra distance = 10 π meters
Time taken for extra distance = π seconds
Horse's speed = distance/time = 10 π/ π → 10 meters/second
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