$${{\mathtt{4}}}^{{\mathtt{0.2}}} = {\mathtt{1.319\: \!507\: \!910\: \!772\: \!894\: \!3}}$$
this is already an approximation - if I round it off to 2 dec places I get 1.32
Now
$$4^{0.2}=4^{1/5}=\sqrt[5]{4}$$
Now id the answer really is 1.3195079 then $$1.3195079^5$$ must equal 4
lets see if it does
$${{\mathtt{1.319\: \!507\: \!9}}}^{{\mathtt{5}}} = {\mathtt{3.999\: \!999\: \!836\: \!713\: \!459\: \!7}}$$ That is close enough to 4 to me
$${{\mathtt{4}}}^{{\mathtt{0.2}}} = {\mathtt{1.319\: \!507\: \!910\: \!772\: \!894\: \!3}}$$
this is already an approximation - if I round it off to 2 dec places I get 1.32
Now
$$4^{0.2}=4^{1/5}=\sqrt[5]{4}$$
Now id the answer really is 1.3195079 then $$1.3195079^5$$ must equal 4
lets see if it does
$${{\mathtt{1.319\: \!507\: \!9}}}^{{\mathtt{5}}} = {\mathtt{3.999\: \!999\: \!836\: \!713\: \!459\: \!7}}$$ That is close enough to 4 to me