How can I modify 0=x^4(x-43)+40x^2(18x-145)+16(1375x-1884) further? I do not want to expand it, instead I want to shorten it, if you know what I mean so I can find the zeros. Please give step by step instructions.
hi Gibsonj338,
$$0=x^4(x-43)+40x^2(18x-145)+16(1375x-1884)$$
I do not know any way to do this without expanding first and then looking for factors
in this case (x-12) is a factor.
12 is the only real solution. There are 2 irrational solutions and 2 complex solutions