A property of logarithms is that log(a) + log(b) = log(a*b) so
log(2x-3) + log(4x + 2) = log(3) becomes
log[(2x - 3)*(4x + 2)] = log(3)
So we must have that (2x - 3)*(4x + 2) = 3
Expand the bracketed terms to get 8x2 -8x - 6 = 3
Subtract 3 from both sides
8x2 -8x - 9 = 0
Solve for the two values of x using the quadratic formula
x = (8 ± √(64 - 4*8*(-9)) )/(2*8)
x ≈ 1.673 and x = -0.673
A property of logarithms is that log(a) + log(b) = log(a*b) so
log(2x-3) + log(4x + 2) = log(3) becomes
log[(2x - 3)*(4x + 2)] = log(3)
So we must have that (2x - 3)*(4x + 2) = 3
Expand the bracketed terms to get 8x2 -8x - 6 = 3
Subtract 3 from both sides
8x2 -8x - 9 = 0
Solve for the two values of x using the quadratic formula
x = (8 ± √(64 - 4*8*(-9)) )/(2*8)
x ≈ 1.673 and x = -0.673