+12 No example on textbook so can someone please explain the steps?
Thank you.
+66 What exactly do you mean by solve? Do you want to multiply this? In that case you just need to apply the Distributive law, which is $$a \cdot (b + c) = a \cdot b + a \cdot c$$.
If you dont have any idea how to do stuff like that, i recommend http://www.webmath.com/polymult.html.
I just found that website googling, but it seems to be exactly what you want. Enter the assignment and it will explain what to do step by step.
A brief and unfortunatly badly formated solution:
$$(x-4)(x+7)(5x-1) = (x-4)(x+7)(5x) + (x-4)(x+7)(-1)
= (x-4)(x)(5x) + (x-4)(7)(5x) + (x-4)(x)(-1) + (x-4)(7)(-1)
= (x)(x)(5x) + (-4)(x)(5x) + (x)(7)(5x) + (-4)(7)(5x) + (x)(x)(-1) + (-4)(x)(-1) + (x)(7)(-1) + (-4)(7)(-1)
=5x^3-20x^2+35x^2-140x-x^2+4x-7x+28 = 5x^3 +14x^2-143x+28$$
+66 What exactly do you mean by solve? Do you want to multiply this? In that case you just need to apply the Distributive law, which is $$a \cdot (b + c) = a \cdot b + a \cdot c$$.
If you dont have any idea how to do stuff like that, i recommend http://www.webmath.com/polymult.html.
I just found that website googling, but it seems to be exactly what you want. Enter the assignment and it will explain what to do step by step.
A brief and unfortunatly badly formated solution:
$$(x-4)(x+7)(5x-1) = (x-4)(x+7)(5x) + (x-4)(x+7)(-1)
= (x-4)(x)(5x) + (x-4)(7)(5x) + (x-4)(x)(-1) + (x-4)(7)(-1)
= (x)(x)(5x) + (-4)(x)(5x) + (x)(7)(5x) + (-4)(7)(5x) + (x)(x)(-1) + (-4)(x)(-1) + (x)(7)(-1) + (-4)(7)(-1)
=5x^3-20x^2+35x^2-140x-x^2+4x-7x+28 = 5x^3 +14x^2-143x+28$$
