Hi!,

2^x-2^{x-1}=4

I lose the x if i use my 'normal method of immediately 4=2^2 and bringing everything down.

x-(x-1)=2

Guest Sep 8, 2017

#1**+1 **

\(2^{x}-2^{x-1} =4 \)now factor out to get

\(2^{x-1} (2^{1}- 1)=4\)

\(2^{x-1}(1) =4\)

\(2^{x-1}=4 \) since we know that \(2^{2}=4\)

then x-1 =2 so x =3.

Check 2^3 - 2^2 = 8 - 4 =4

frasinscotland
Sep 8, 2017