Hi!,
2^x-2^{x-1}=4
I lose the x if i use my 'normal method of immediately 4=2^2 and bringing everything down.
x-(x-1)=2
+71 \(2^{x}-2^{x-1} =4 \)now factor out to get
\(2^{x-1} (2^{1}- 1)=4\)
\(2^{x-1}(1) =4\)
\(2^{x-1}=4 \) since we know that \(2^{2}=4\)
then x-1 =2 so x =3.
Check 2^3 - 2^2 = 8 - 4 =4
