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 How did \(-3i\bar{z}\) become -3b-3ia?  When I expanded it, I got \(-3i(a-bi)=-3ia-3bi\)?

 Apr 14, 2019
 #1
avatar+111438 
+1

-3i (z conjugate)  =

 

-3 i ( a - bi)  =

 

-3i a   + 3b i^2  =

 

-3b - 3 i a

 

 

cool cool cool

 Apr 14, 2019

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