+0  
 
-1
318
2
avatar+27 

So the equation is this:


\(9sec^2\theta tan\theta - 12tan\theta=0\)

 

And somehow it factors out to this:

 

\(3tan\theta (3sec^2\theta - 4)=0\)

 

Can someone explain to me the factoring steps? I'm very lost
Thanks!
P.S. I hate pearson my math lab with a burning passion

CurlyFry  Apr 16, 2017
 #1
avatar+86859 
+3

9sec^2 (x)  tan(x)   -  12tan (x)   = 0       re-write as

 

9tan (x) sec^2 (x)  - 12 tan (x)   =   0

 

Factor out the greatest common factor,   3tan(x)

 

3tan (x)  [ 3 sec^2 (x)  - 4  ]  = 0

 

 

cool cool cool

CPhill  Apr 16, 2017
 #2
avatar+27 
+1

Ohhh duh, thanks so much :)

CurlyFry  Apr 16, 2017

8 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.