+0  
 
0
317
2
avatar

how do graph quadratic equations?

 Jun 11, 2014

Best Answer 

 #2
avatar+97576 
+5

$$y=ax^2+bx+c\qquad a\ne0$$     

this is a parabola.

If a>0 then it is concave up, If a<0 then it is concave down.

The y intercept is c

$$\mbox{The axis of symmetry is }\qquad x=\dfrac{-b}{2a}\\

\mbox{Substitute in this value of x to get the y co-ordinate of the vertex}$$

 

The roots, x intercepts are 

$$x=\dfrac{-b}{2a}\pm \dfrac{\sqrt{b^2-4ac}}{2a}$$

That is usually enough.  

 Jun 12, 2014
 #1
avatar+259 
0

Please, put your question in a more appriate and mathematically correct shape. Your question is too general.

 Jun 11, 2014
 #2
avatar+97576 
+5
Best Answer

$$y=ax^2+bx+c\qquad a\ne0$$     

this is a parabola.

If a>0 then it is concave up, If a<0 then it is concave down.

The y intercept is c

$$\mbox{The axis of symmetry is }\qquad x=\dfrac{-b}{2a}\\

\mbox{Substitute in this value of x to get the y co-ordinate of the vertex}$$

 

The roots, x intercepts are 

$$x=\dfrac{-b}{2a}\pm \dfrac{\sqrt{b^2-4ac}}{2a}$$

That is usually enough.  

Melody Jun 12, 2014

30 Online Users

avatar
avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.