How do I calculate this? tan x=-2. sin x=? What is the formula?
To start with x muxt be in the 2nd or 4th quad because tanx is neg
this means that sinx can be neg or pos
-------------------
Now forget about the negative for the moment
Draw a right angled triangle.
Put x in one of the acute angles
tanx=2/1 so put 2 on the opposite side and 1 on the adjacent side.
Use Pythagoras' theorum to get the hypotenuse. $${\sqrt{{\mathtt{5}}}}$$
So reading off the triangle $$sinx=\pm\frac{2}{\sqrt5}$$
If tan x=-2, then either y = 2 and x = -1, or y= -2 and x = 1.
And regardless, r = √5 ...... And sinx = y/r
So, either sin x = 2/√5 and x is a 2nd quadrant angle
Or, sin x = -2/√5 and x is a 4th quadrant angle
How do I calculate this? tan x=-2. sin x=? What is the formula?
To start with x muxt be in the 2nd or 4th quad because tanx is neg
this means that sinx can be neg or pos
-------------------
Now forget about the negative for the moment
Draw a right angled triangle.
Put x in one of the acute angles
tanx=2/1 so put 2 on the opposite side and 1 on the adjacent side.
Use Pythagoras' theorum to get the hypotenuse. $${\sqrt{{\mathtt{5}}}}$$
So reading off the triangle $$sinx=\pm\frac{2}{\sqrt5}$$