How do I center a small circle into a bigger one perfectly...
The equation of a circle is
\(\boxed{(x-h)^2+(y-k)^2=r^2}\)where (h,k) is the centre and r is the radius.
so if you have 2 circle equations with the same centre but with different radii, they will be concentric circles.
eg
\((x+1)^2+(y-3)^2=16\qquad and\\ (x+1)^2+(y-3)^2=9\)
How do I center a small circle into a bigger one perfectly...
The equation of a circle is
\(\boxed{(x-h)^2+(y-k)^2=r^2}\)where (h,k) is the centre and r is the radius.
so if you have 2 circle equations with the same centre but with different radii, they will be concentric circles.
eg
\((x+1)^2+(y-3)^2=16\qquad and\\ (x+1)^2+(y-3)^2=9\)
Thanks, Melody.....here's another method.....
Draw any size circle
Draw any chord within the circle
Draw a perpendicular bisector to this chord and extend it to both edges of the circle.....this will be a diameter
Draw a perpendicular bisector to this diameter
The point of bisection is the center of the circle
Now any size circle(s) can be costructed using this point as their center(s)