y=1/4x+1=2y=2x-4
how do i do this
y=1/4x+1 2y=2x-4
\(y=\frac{1}{4}x+1\\2y=2x-4\)
\(2\cdot( \frac{1}{4}x+1)=2x-4\\\frac{1}{2}x+2=2x-4\\6=\frac{3}{2}x\) [\( y=\frac{1}{4}x+1\)
\(x=4\)
\(y=1+1\)
\(y=2\)
!
Thanks Alan! I correct that.