Let \(f(x) = \begin{cases} 9x+16 &\text{if }x<2, \\ 2x-14&\text{if }x\ge2. \end{cases} \)If f(x)=-2, find the sum of all possible values of x.

Please help me, how am I supposed to proceed with this?

Guest Jun 9, 2020

#1**0 **

Since f(x) = 2, there are two ways that the answer is 2.

First way: if x < 2: 9x + 16 = 2 ---> 9x = -14 ---> x = -14/9.

Second way: if x >= 2: 2x - 14 = 2 ---> 2x = 16 ---> x = 8

You will now need to add the two possible values for x ...

geno3141 Jun 9, 2020

#2**0 **

Oh, so what I do is just plug in the value -2 for 9x+16 and 2x-14?

By the way, there's a mistake because f(x)= -2, not 2.

Guest Jun 9, 2020