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(5+6i)(5-6i)+14

 Nov 3, 2015

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 #1
avatar+26400 
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(5+6i)(5-6i)+14

 

\((5+6i)(5-6i)+14\\ =5^2 -(6i)^2+14\\ = 25-36i^2+14\\ =39-36i^2\qquad | \qquad \boxed{~i^2=-1~}\\ =39-36\cdot(-1)\\ =39+36\\ =75\\ \mathbf{(5+6i)(5-6i)+14 = 75}\)

 

laugh

 Nov 3, 2015
 #1
avatar+26400 
+30
Best Answer

(5+6i)(5-6i)+14

 

\((5+6i)(5-6i)+14\\ =5^2 -(6i)^2+14\\ = 25-36i^2+14\\ =39-36i^2\qquad | \qquad \boxed{~i^2=-1~}\\ =39-36\cdot(-1)\\ =39+36\\ =75\\ \mathbf{(5+6i)(5-6i)+14 = 75}\)

 

laugh

heureka Nov 3, 2015

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