how do i do this
cos-1(8/17)
A) \(cos^{ -1}(a) \ means \ arccos \ (a)\) Normal pocket calculator
\(cos^{-1}(\frac{8}{17})=arccos(\frac{8}{17})=arccos (0.470588235)=61.93°\)
B) \(cos^{ -1}(a) \ means \ \frac{1}{cos (a)}\)
\(\large cos^{-1}(\frac{8}{17}deg)=\frac{1}{cos(\frac{8}{17}deg)}=\frac{1}{1}=1\)
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