+118723 $$\\1200=600(1.06)^n\\\\
2=1.06^n\\\\
log(2)=log(1.06^n)\\\\
log(2)=nlog(1.06)\\\\
n=\frac{log(2)}{log(1.06)}$$
$${\frac{{log}_{10}\left({\mathtt{2}}\right)}{{log}_{10}\left({\mathtt{1.06}}\right)}} = {\mathtt{11.895\: \!661\: \!045\: \!941\: \!876\: \!8}}$$
there you go, leave it in the bank for 12 years.
+118723 $$\\1200=600(1.06)^n\\\\
2=1.06^n\\\\
log(2)=log(1.06^n)\\\\
log(2)=nlog(1.06)\\\\
n=\frac{log(2)}{log(1.06)}$$
$${\frac{{log}_{10}\left({\mathtt{2}}\right)}{{log}_{10}\left({\mathtt{1.06}}\right)}} = {\mathtt{11.895\: \!661\: \!045\: \!941\: \!876\: \!8}}$$
there you go, leave it in the bank for 12 years.
