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How do I find the angles of a right triangle with only the sides

 Apr 8, 2015

Best Answer 

 #1
avatar+23254 
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If you want to know the size of angle A and you know the value of the side opposite ∠A (side a) and you know the value of the hypotenuse (side c), use sine:  

     sin(A) =  opposite / hypotenuse   --->   sin(A) = a/c   --->   A  =  sin-1(a/c)

If you want to know the size of angle A and you know the value of the side adjacent ∠A (side b) and you know the value of the hypotenuse (side c), use cosine:  

     cos(A) =  adjacent/ hypotenuse   --->   cos(A) = b/c   --->   A  =  cos-1(b/c)

If you want to know the size of angle A and you know the value of the side opposite ∠A (side a) and you know the value of the side adjacent ∠A (side b), use tangent:  

     tan(A) =  opposite / adjacent   --->   tan(A) = a/b   --->   A  =  tan-1(a/b)

 Apr 8, 2015
 #1
avatar+23254 
+5
Best Answer

If you want to know the size of angle A and you know the value of the side opposite ∠A (side a) and you know the value of the hypotenuse (side c), use sine:  

     sin(A) =  opposite / hypotenuse   --->   sin(A) = a/c   --->   A  =  sin-1(a/c)

If you want to know the size of angle A and you know the value of the side adjacent ∠A (side b) and you know the value of the hypotenuse (side c), use cosine:  

     cos(A) =  adjacent/ hypotenuse   --->   cos(A) = b/c   --->   A  =  cos-1(b/c)

If you want to know the size of angle A and you know the value of the side opposite ∠A (side a) and you know the value of the side adjacent ∠A (side b), use tangent:  

     tan(A) =  opposite / adjacent   --->   tan(A) = a/b   --->   A  =  tan-1(a/b)

geno3141 Apr 8, 2015

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