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find the area of a triangle with A=29 degrees b=49 and c=50

Guest Apr 20, 2017
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find the area of a triangle with A=29 degrees b=49 and c=50

 

Formula:

\(\begin{array}{|rcll|} \hline \text{Area} &=& \frac12 \cdot b\cdot c\cdot \sin(A) \\ \hline \end{array} \)

 

 

\(\begin{array}{|rcll|} \hline \text{Area} &=& \frac12 \cdot 49\cdot 50\cdot \sin(29^{\circ}) \\ &=& \frac12 \cdot 49\cdot 50\cdot 0.48480962025 \\ &=& 593.891784802 \\ \hline \end{array} \)

 

laugh

heureka  Apr 20, 2017

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