how do i find the area of the triangle?

find the area of a triangle with A=29 degrees b=49 and c=50

Formula:

\(\begin{array}{|rcll|} \hline \text{Area} &=& \frac12 \cdot b\cdot c\cdot \sin(A) \\ \hline \end{array} \)

\(\begin{array}{|rcll|} \hline \text{Area} &=& \frac12 \cdot 49\cdot 50\cdot \sin(29^{\circ}) \\ &=& \frac12 \cdot 49\cdot 50\cdot 0.48480962025 \\ &=& 593.891784802 \\ \hline \end{array} \)