how do I find the derivative of f(x)=1.2x^3-2^1.5x+√2

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I don't understand how 1.2x^3 turns into 3.6x2

Guest Feb 17, 2015

+118723

+5

Best Answer

$$\\ f(x)=1.2x^3-2^{1.5}x+\sqrt2\\\\
f'(x)=3*1.2x^2-2^{1.5}\\\\
f'(x)=3.6x^2-2\sqrt2\\\\$$

NOTE:

$$\\y=ax^n\qquad then\qquad y'=n*a*x^{n-1}\\\\
so\;if\;
y=1.2x^3\qquad then\qquad y'=3*1.2*x^{2}=3.6x^2\\\\$$

Melody Feb 17, 2015

Melody · Answer 1 · 2015-02-17T04:58:43

$$\\ f(x)=1.2x^3-2^{1.5}x+\sqrt2\\\\
f'(x)=3*1.2x^2-2^{1.5}\\\\
f'(x)=3.6x^2-2\sqrt2\\\\$$

NOTE:

$$\\y=ax^n\qquad then\qquad y'=n*a*x^{n-1}\\\\
so\;if\;
y=1.2x^3\qquad then\qquad y'=3*1.2*x^{2}=3.6x^2\\\\$$

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