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How do I find the function domain?

 
2+((x^2)/(1-x))
 Jul 14, 2015

Best Answer 

 #1
avatar+118587 
+5
2+((x^2)/(1-x))

$$2+\frac{x^2}{1-x}$$

To work out the domain, the idea is to work out what x can be.
It is usually easier to work out what x can't be though.

So with this one.
you cannot divide by zero so

$$\\1-x\ne 0\rightarrow\;\;x\ne 1$$

Domain: All Real x where x is not equal to 1
or
Domain: All Real x except x=1


I think x can be anything else, I will double check by graphing it.

https://www.desmos.com/calculator/y4mkbuvn9d

Y
es that is fine :)
 Jul 14, 2015
 #1
avatar+118587 
+5
Best Answer
2+((x^2)/(1-x))

$$2+\frac{x^2}{1-x}$$

To work out the domain, the idea is to work out what x can be.
It is usually easier to work out what x can't be though.

So with this one.
you cannot divide by zero so

$$\\1-x\ne 0\rightarrow\;\;x\ne 1$$

Domain: All Real x where x is not equal to 1
or
Domain: All Real x except x=1


I think x can be anything else, I will double check by graphing it.

https://www.desmos.com/calculator/y4mkbuvn9d

Y
es that is fine :)
Melody Jul 14, 2015

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