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How do I find the least amount of wrapping paper for a box that is 3 1/2 feet by 1 1/3 feet by 2 1/4 feet?

 Apr 9, 2020

Best Answer 

 #2
avatar+111329 
+1

Note that   3 1/2  =  7/2        1  1/3   =  4/3       2  1/4  =   9/4

 

The  area  =   2 ( the sum of the products  of all three dimensions taken two at a  time )  =

 

( 7/2 * 4/3   +  4/3 * 9/4  +  7/2* 9/4 )  =

 

( 28/6  + 36/12  +  63/8)   =

 

(14/3  + 3   + 63/8)   =

 

 ( 8 * 14  + 3 * 63)  / 24   + 3  =

 

301/24  +  3   =

 

12 + 13/24  +  3  =

 

15 + 13/24  ft^2

 

 

cool cool cool

 Apr 9, 2020
 #1
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0

The minimum area is 15 5/6 square feet.

 Apr 9, 2020
 #2
avatar+111329 
+1
Best Answer

Note that   3 1/2  =  7/2        1  1/3   =  4/3       2  1/4  =   9/4

 

The  area  =   2 ( the sum of the products  of all three dimensions taken two at a  time )  =

 

( 7/2 * 4/3   +  4/3 * 9/4  +  7/2* 9/4 )  =

 

( 28/6  + 36/12  +  63/8)   =

 

(14/3  + 3   + 63/8)   =

 

 ( 8 * 14  + 3 * 63)  / 24   + 3  =

 

301/24  +  3   =

 

12 + 13/24  +  3  =

 

15 + 13/24  ft^2

 

 

cool cool cool

CPhill Apr 9, 2020

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