How do I find the period of y=4 cos(2x+2pi)?
2pi/B
B=2
2pi/2
KCF
Keep 2pi
Change it to multiplication
Flip 2. It's now 1/2
2pi*1/2 = pi
y=4 cos(2x+2pi) write this as
y = 4 cos [ 2 (x+ pi) ]
The 2 tells us how many periods are in 2pi rads....so each period is pi rads in length
