How do I find the sum of 2400 increased 4 perecent per a period for 40 periods?

2400(1.04)^40 = 11522.45

No, it is the sum of 2400 increased 4 percent per a period over the total of 40 periods:

(2400 x 1.04)  +  (2400 x 1.04 x 1.04) + (2400 x 1.04 x 1.04 x 1.04)   etc.    for a total of 40 periods.

No, sorry, not making sense. Here, I will give you the word problem that I am trying to find a mathematical solution to. Over a 40 year period a person pays property tax on their dwelling. In year 1 they pay $2400. They get a 4 percent increase in the tax rate every year, hence year 2 they will pay $2400 x 1.04 =  $2496.  Now, after 40 years of paying property taxes, I am trying to see what the total of payments are. There is no way they paid $2 million for property taxes over the years. See what I am trying to get at?

Are you trying to calculate the value of a series of payments of 2400  over 40 periods with simple interest of 4% per period? ?

\(\sum_{1}^{40}\)2400(1.04)^n = 237183.69  sound about right?

Yes, I think that is the correct answer based on the sum series type word problem I posed. How did you calculate that? I am studying costs of house ownership based on inflation rates and would like an online calculator that could do that for me. Thanks by the way!

Hold on, did you use Wolfram online for the calcs, lol?

Here is the website I used: 

https://www.mathsisfun.com/numbers/sigma-calculator.html

In reality, I THINK we may still not have QUITE the correct answer...I think the first year the payment is 2400 then the NEXT year it goes up 4 percent etc etc

so it would be

\( \sum_{0}^{39}\)2400(1.04)^n  = 228061.24       But that is not what I was asked.......

EP: From "Guest #4" answer, your answer #9 is the correct answer. And it is the sum of a "Geometric Series", whose 1st. term=2,400, common ratio =1.04 and the number of terms=40.