How do I find the value of = (-200sin (20π t))×(10cos (20πt))

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How do I find the value of p (t)= (-200sin (20π t))×(10cos (20πt))

Guest Jul 15, 2015

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Best Answer

$\\=-2000sin (20\pi t)cos (20\pi t))\\\\ =-1000*2sin (20\pi t)cos (20\pi t))\\\\ =-1000\;sin (40\pi t)\\\\$

It t is an integer than this equals 0

otherwise I think it is fully simplified.

Melody Jul 15, 2015

Melody · Answer 1 · 2015-07-15T03:41:42

$\\=-2000sin (20\pi t)cos (20\pi t))\\\\ =-1000*2sin (20\pi t)cos (20\pi t))\\\\ =-1000\;sin (40\pi t)\\\\$

It t is an integer than this equals 0

otherwise I think it is fully simplified.