how do I get the total of 2000$ at 12% intrest anually compounded for 10years

A = P(1 + r)^{n}

A = final amount

P = beginning amount = $2000.00

r = yearly interest rate as a decimal = 0.12

n = number of years = 10

A = 2000(1 + 0.12)^{10} = $6211.70

Please make your question clearer!. Do you mean how much money you have to have today to get $2000 in 10 years? Or, how much money you have to deposit every year to get $2000 in 10 years?.