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How do I go about factoring 125x3-8?

as in the method, not just the answer...

Guest Jan 23, 2018
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 #1
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125x^3  - 8

 

This is the difference of cubes

 

The  factorization  of  a^3  - b^3  =  ( a - b) (a^2  + ab  + b^2)

 

"a"  is   the cube root of the first term  = 5x

"b" is the cube root of the second term  =  2

 

So we have

 

( 5x  - 2)   ( [ 5x ]^2  +  [ 5x * 2 ] + 2^2 ]  =

 

(5x - 2) (25x^2  + 10x  + 4 )

 

 

 

cool cool cool

CPhill  Jan 24, 2018

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