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how do i simplify (2f^2g^3/3fg)^4??

 

8th grade algebra

 Jan 14, 2015

Best Answer 

 #3
avatar+118677 
+5

$$\\(\frac{2f^2g^3}{3fg})^4\\\\
=(\frac{2ffggg}{3fg})^4\\\\
=(\frac{2fgg}{3})^4\\\\
=(\frac{2fg^2}{3})^4\\\\
=\frac{2^4f^4(g^2)^4}{3^4}\\\\
=\frac{16f^4g^8}{81}\\\\$$

.
 Jan 14, 2015
 #1
avatar+12 
0

first distribute the exponent outside the paretheses

 Jan 14, 2015
 #2
avatar+12 
0

then combine the exponents withe the same base and you should be good

 Jan 14, 2015
 #3
avatar+118677 
+5
Best Answer

$$\\(\frac{2f^2g^3}{3fg})^4\\\\
=(\frac{2ffggg}{3fg})^4\\\\
=(\frac{2fgg}{3})^4\\\\
=(\frac{2fg^2}{3})^4\\\\
=\frac{2^4f^4(g^2)^4}{3^4}\\\\
=\frac{16f^4g^8}{81}\\\\$$

Melody Jan 14, 2015

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