how do i simplify sqrt4(16*z^8)?

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Guest Jul 14, 2015

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Best Answer

Think of this as

$(16z^8)^{\frac{1}{4}}\rightarrow16^{\frac{1}{4}}\times(z^8)^{\frac{1}{4}}\rightarrow2z^2$

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Alan Jul 14, 2015

Alan · Answer 1 · 2015-07-14T02:30:06

Think of this as

$(16z^8)^{\frac{1}{4}}\rightarrow16^{\frac{1}{4}}\times(z^8)^{\frac{1}{4}}\rightarrow2z^2$

.