how do i solve 112a2 - 168a +63? I know the basic process, but setting it up is hard.
Solve for a: 112 a^2-168 a+63 = 0
Divide both sides by 112: a^2-(3 a)/2+9/16 = 0
Write the left hand side as a square: (a-3/4)^2 = 0
Take the square root of both sides: a-3/4 = 0
Add 3/4 to both sides: Answer: |a = 3/4
